Energia Mediante Vapor Aire O Gas — Solucionario Work

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Energia Mediante Vapor Aire O Gas — Solucionario Work

¡Claro! A continuación, te presento un guía detallada sobre "Energía mediante vapor, aire o gas: Solucionario Work":

Cálculo de flujo másico necesario para producir una potencia específica (ej. 1000 hp). Compresores: Compresión isotérmica vs. adiabática. Motores de Combustión: Ciclos Otto y Diesel. 4. Ejemplo Práctico de Trabajo energia mediante vapor aire o gas solucionario work

Tipos de Sistemas

  1. At turbine inlet (4 MPa, 400°C): from superheated tables → ( h_3 = 3214.5 , kJ/kg ), ( s_3 = 6.7690 , kJ/(kg·K) )
  2. For isentropic expansion to 10 kPa: ( s_4 = s_3 = 6.7690 ). At 10 kPa: ( s_f=0.6493, s_g=8.1502 ). Quality ( x = (6.7690-0.6493)/(8.1502-0.6493) = 0.815 ). Then ( h_4 = h_f + x h_fg = 191.83 + 0.815×2392.8 = 2141.5 , kJ/kg )
  3. Turbine work: ( w_t = 3214.5 - 2141.5 = 1073.0 , kJ/kg )
  4. Pump work: ( v_1 ≈ 0.00101 , m³/kg ). ( w_p = 0.00101 × (4000-10) = 4.03 , kJ/kg )
  5. Net work: ( w_net = 1073.0 - 4.03 = 1068.97 , kJ/kg )
  6. Heat input: ( h_2 ≈ h_1 + w_p = 191.83 + 4.03 = 195.86 ). Then ( q_in = h_3 - h_2 = 3214.5 - 195.86 = 3018.64 , kJ/kg )
  7. Efficiency: ( \eta = 1068.97/3018.64 = 0.354 ) (35.4%)

Esto supera ampliamente a cualquier ciclo simple (máx 45% para gas simple, 35% para vapor simple). ¡Claro

[ W = \int P dV ]

En una turbina, el trabajo realizado se puede calcular como: At turbine inlet (4 MPa, 400°C): from superheated

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